LeetCode in Cpp

17. Letter Combinations of a Phone Number

Medium

Given a string containing digits from 2-9 inclusive, return all possible letter combinations that the number could represent. Return the answer in any order.

A mapping of digit to letters (just like on the telephone buttons) is given below. Note that 1 does not map to any letters.

Example 1:

Input: digits = “23”

Output: [“ad”,”ae”,”af”,”bd”,”be”,”bf”,”cd”,”ce”,”cf”]

Example 2:

Input: digits = “”

Output: []

Example 3:

Input: digits = “2”

Output: [“a”,”b”,”c”]

Constraints:

• 0 <= digits.length <= 4
• digits[i] is a digit in the range ['2', '9'].

Solution

#include <vector>
#include <string>
#include <unordered_map>
using namespace std;

class Solution {
public:
    vector<string> letterCombinations(string digits) {
        if (digits.empty()) {
            return {};
        }

        vector<string> letters = {"", "", "abc", "def", "ghi", "jkl", "mno", "pqrs", "tuv", "wxyz"};
        vector<string> ans;
        string curr;
        findCombinations(0, digits, letters, curr, ans);
        return ans;
    }

private:
    void findCombinations(int start, const string& nums, const vector<string>& letters, string& curr, vector<string>& ans) {
        if (curr.length() == nums.length()) {
            ans.push_back(curr);
            return;
        }

        int n = nums[start] - '0';
        for (char ch : letters[n]) {
            curr.push_back(ch);
            findCombinations(start + 1, nums, letters, curr, ans);
            curr.pop_back();
        }
    }
};

This site is open source. Improve this page.