Easy
Given an integer array nums
, move all 0
’s to the end of it while maintaining the relative order of the non-zero elements.
Note that you must do this in-place without making a copy of the array.
Example 1:
Input: nums = [0,1,0,3,12]
Output: [1,3,12,0,0]
Example 2:
Input: nums = [0]
Output: [0]
Constraints:
1 <= nums.length <= 104
-231 <= nums[i] <= 231 - 1
Follow up: Could you minimize the total number of operations done?
#include <vector>
class Solution {
public:
void moveZeroes(std::vector<int>& nums) {
int firstZero = 0;
for (int i = 0; i < nums.size(); i++) {
if (nums[i] != 0) {
swap(firstZero, i, nums);
firstZero++;
}
}
}
private:
void swap(int index1, int index2, std::vector<int>& numbers) {
int val2 = numbers[index2];
numbers[index2] = numbers[index1];
numbers[index1] = val2;
}
};