Medium
Given an array of integers nums and an integer k, return the total number of continuous subarrays whose sum equals to k.
Example 1:
Input: nums = [1,1,1], k = 2
Output: 2
Example 2:
Input: nums = [1,2,3], k = 3
Output: 2
Constraints:
1 <= nums.length <= 2 * 104-1000 <= nums[i] <= 1000-107 <= k <= 107#include <vector>
#include <unordered_map>
class Solution {
public:
    int subarraySum(std::vector<int>& nums, int k) {
        int tempSum = 0;
        int ret = 0;
        std::unordered_map<int, int> sumCount;
        sumCount[0] = 1;
        
        for (int num : nums) {
            tempSum += num;
            if (sumCount.find(tempSum - k) != sumCount.end()) {
                ret += sumCount[tempSum - k];
            }
            if (sumCount.find(tempSum) != sumCount.end()) {
                sumCount[tempSum]++;
            } else {
                sumCount[tempSum] = 1;
            }
        }
        return ret;
    }
};